List<Port> is not getting saved in DUTs.xml

Technical
1

Hi Team,

I have created a custom DUT class that inherits from Dut.

In that class I have created a Property of type List Port>

When I use DutSettings.Current.Save();, XML file is created ,but List is always null.

public class CustomDutSettings : Dut
{

    [Display(CommonVariableNames.PinDetails, Order: 5)]
    public List<Port> PinDetails { get; set; }

Is there something I missed out?

Regards
Jestin CI

1 Like
2

@justin_c_i you also need to create the individual Ports and then initialize your list:

Since you want to save these values, you will want to remove the [XmlIgnore] from that example:

    public class ListTestInstr : Instrument
    {
        public Port P1 { get; set; }
        public Port P2 { get; set; }

        public List<Port> Ports { get; set; }

        public ListTestInstr()
        {
            P1 = new Port(this, "Port1");
            P2 = new Port(this, "Port2");
            Ports = new List<Port> { new Port(this, "Port3"), new Port(this, "Port4") };
        }
    }
1 Like
3

I used the following class

public class CustomDutSettings : Dut
{
private string dutName;
private List portdetails;

    public Port P1 { get; set; }
    public Port P2 { get; set; }

    public List<Port> Ports { get; set; }

    /// <summary>
    /// Initializes a new instance of the <see cref="CustomDutSettings"/> class.
    /// </summary>
    public CustomDutSettings()
    {
        this.ID = string.Empty;
        this.SerialNumber = string.Empty;
        this.DutName = string.Empty;
        this.Result = DutResult.UnDefined;
        this.PanelBoard = PanelBoardEnum.PANEL1;
        this.IsEnabled = true;
        this.TestOperations = new List<TestOperation>();
        this.PinDetails = new List<PinDetails>();
        this.PinPrefix = "P";
        this.Pins = 1;

        P1 = new Port(this, "Port1");
        P2 = new Port(this, "Port2");
        Ports = new List<Port> { new Port(this, "Port3"), new Port(this, "Port4") };
    }

@brennen_direnzo I used exactly same code, but still Ports are empty in the XML.

image
image1357×174 10.1 KB

2 Likes
4

So, at that point, a Port just exists, but there are no settings associated with it. The values are set when you map the ports in the Connections Settings:
image

In Connections.xml:

<?xml version="1.0" encoding="utf-8"?>
<ConnectionSettings type="OpenTap.ConnectionSettings">
  <RfConnection type="OpenTap.RfConnection" Source="">
    <CableLoss />
    <Name>Route1</Name>
    <Port1 Name="PortA">
      <Device type="OpenTap.Plugins.PluginDevelopment.TwoPortInstrument" Source="OpenTap.InstrumentSettings">Inst1</Device>
    </Port1>
    <Port2 Name="PortA">
      <Device type="OpenTap.Plugins.PluginDevelopment.FourPortDut" Source="OpenTap.DutSettings">FourPortDut</Device>
    </Port2>
    <Via>
      <SwitchPosition type="OpenTap.SwitchPosition" Name="PosA">
        <Device type="OpenTap.Plugins.PluginDevelopment.TwoPositionSwitchInstrument" Source="OpenTap.InstrumentSettings">Switch</Device>
      </SwitchPosition>
    </Via>
  </RfConnection>
  <Package.Dependencies>
    <Package Name="OpenTAP" Version="9.12.0+78ddca2e" />
  </Package.Dependencies>
</ConnectionSettings>
1 Like
5

@brennen_direnzo ,
If I need to create List Port> in DUTs and save it in XML , is not possible.?
Just save List Port> in XML, I will Be adding Port name like P1,P2,P3 and need to save in DUTs.xml.

I will not be Opening Connections Window

1 Like
6

What are you trying to accomplish from there maybe we can point you in the right direction on an approach.

@gordonong has been looking into some updates to switching recently so he may be able to help.

2 Likes
7

@justin_c_i We’re aware the Port information are not serialized into DUT.xml file. The team is working to fix this issue.

3 Likes